Worked Examples To Eurocode 2 Volume 2 -

The design shear force is:

The slab is checked for punching shear:

The required reinforcement area is calculated as:

The provided reinforcement area is:

As.provided = (π x (10/2)^2) / 0.2 = 392 mm^2

The column is checked for buckling:

The beam requires additional shear reinforcement. worked examples to eurocode 2 volume 2

The slab requires additional shear reinforcement.

The critical buckling load is:

MEd = 1.35 x (10 x 6^2 / 8) + 1.5 x (5 x 6^2 / 8) = 63.9 kNm The design shear force is: The slab is

The beam is checked for shear resistance:

The provided reinforcement area is:

Ncr = π^2 x 25 x 0.4^4 / (3^2) = 2761 kN The slab is reinforced with a mesh of

λ = 3 / 0.4 = 7.5

A rectangular slab with a span of 4 meters and a thickness of 0.2 meters is subjected to a permanent load of 2 kN/m^2 and a variable load of 1.5 kN/m^2. The slab is reinforced with a mesh of 10 mm diameter bars at 200 mm spacing.